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1. The width of a one-car garage in a residential housing unit in CFB Cold Lake is half of its depth. If the perimeter of the garage is 72 ft, find the width and depth in ft.
a. 13 x 26
b. 14 x 28
c. 12 x 24 --- answer
d. 15 x 30
Solution:
Let
w = width of garage
d = depth of garage
p = perimeter
equation1:
w = (1/2) * d
w = 0.5d
equation2:
perimeter, p = 72 ft
p = 2w + 2d
72 = 2w + 2d
substituting the value of w in equation1 into equation2,
w = 0.5d
72 = 2w + 2d
72 = 2 * 0.5d + 2d
72 = 1d + 2d
72 = 3d
d = 72/3
d = 24 ft
solving now for w
w = 0.5d
w = 0.5 * 24
w = 12 ft
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