***
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1. Seven years from now, Philip will be ten years younger than two times his current age. What will be his age four years from now?
a. 17
b. 34
c. 21 --- answer
d. 24
Solution
step1
Solve for Philip's current age
Let:
x
= Philip current age
x + 7
= Philip's age seven years from now
2x
= two times his current age
2x - 10
= ten years younger than two times his current age
Equation:
x + 7 = 2x − 10
7 + 10 = 2x - x
17 = x
x = 17
(Philip's current age)
step2
Solve for Philip's age four years from now
= 17 + 4
= 21
2. Three years ago, Jade was 14 years younger than twice her age now. How old is she seven years from now?
a. 11
b. 18 --- answer
c. 14
d. 22
Solution
step1
Solve for Jade's current age
Let:
x
= Jade's age now
x - 3
= Jade's age three years ago
2x
= twice her age now
2x - 14
= 14 years younger than twice her age now
Equation:
x - 3 = 2x − 14
14 - 3 = 2x - x
11 = x
x = 11
(Jade's age now)
step2
Solve for Jade's age seven years from now
= 11 + 7
= 18
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***
FREE CFAT Practice Test (Canadian Forces Aptitude Test):
https://www.army-test.com/131.html
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