CFAT Practice Test Questions with Answers in PROBLEM SOLVING - ps025

***

FREE CFAT Practice Test (Canadian Forces Aptitude Test): 

https://www.army-test.com/131.html

***

1. Peter lives 2 km to the south of Andrew's house. James lives 4 km to the north of Andrew's house. Thomas' house is 6 km south of Peter's house. How far is James's house from the house of  Thomas?

a. 6 km

b. 8 km

c. 10 km

d. 12 km  --- answer 

Solution:  

step1: draw

James 

4 km

Andrew 

2 km

Peter

6 km

Thomas

step2: add 

because the house of Thomas is located directly south of the house of James, we can therefore add all the numbers in between

distance from James to Thomas

= 4 + 2 + 6

= 12 km

2. Morphy is 4 times as old as Bobby.

Bobby is twice as old as Dan. Dan is 3 times as old as Garry who is now 4 years old. How old is Morphy now?

a. 94

b. 96   ---  answer 

c. 98

d. 92

Solution 

step1: 

analyze the age relationships

Morphy = 4 x Bobby

Bobby = 2 x Dan

Dan = 3 x Garry

Garry = 4  now

step2: 

start from the given age now 

(Garry's age = 4)

Garry = 4  now

Dan = 3 x Garry

Dan = 3 x 4

Dan = 12

Bobby = 2 x Dan

Bobby = 2 x 12

Bobby = 24

Morphy = 4 x Bobby

Morphy = 4 x 24

Morphy = 96

3. Smith is now 24 years old. Smith is twice as old as Hudson when Smith was as old as Hudson is now. How old is  Hudson now? 

a. 18   --- answer 

b. 16

c. 14

d. 12

Given 

24 years old

= Smith's age now

Solution 

Let x = Hudson's age now

age difference now

= 24 - x

age difference when Smith was half his own age

= x - (24/2)

since age difference is always the same now and in the past, 

 NOW         PAST

(24 - x) = x - (24/2)

24 - x = x - 12

24 + 12 = x + x

2x = 36

x = 36/2

x = 18

(Hudson's age now)

Checking answer:

difference in age is always equal

age difference now

= 24 - 18

= 6

when Smith was 18, which is Hudson's age now, this was 6 years ago

Smith's age 6 years ago is

= 24 - 6

= 18

since the age difference is always equal, we must also subtract 6 from Hudson's age now

Hudson's age 6 years ago

= 18 - 6

= 12

so, when 

Smith was 18, Hudson  was 12, 

Smith is now 24, which was twice of Hudson's age of 12 (that's 6 years ago)

 

***

Link to my CFAT Practice YouTube playlist

CFAT study guides from Amazon

***

FREE CFAT Practice Test (Canadian Forces Aptitude Test): 

https://www.army-test.com/131.html

***

CFAT Practice Test Questions with Answers in PROBLEM SOLVING - ps024

***

FREE CFAT Practice Test (Canadian Forces Aptitude Test): 

https://www.army-test.com/131.html

***

1. Which one below has the highest value?

A. 5 × 77 - 25

B. 1200 - 14 × 5

C. 7200 ÷ 12 × 2

D. 900 + 74 × 2

Answer:  C

Solution 

using BEDMAS 

A. 15 × 77 - 55 

= 1155 - 55

= 1100

B. 1200 - 14 * 5 

= 1200 - 70

= 1130

C. 7200 ÷ 12 × 2

= 600 × 2

= 1200  (highest)

D. 900 + 74 × 2

= 900 + 148

= 1048

2. What is the value of x?

21 - x + 17 + 3x = 4x

a. 38

b. 76

c. 17

d. 19  ---  answer

Solution 

21 - x + 17 + 3x = 4x

38 + 2x = 4x

38 = 4x - 2x

38 = 2x

x = 38/2

x = 19

checking: 

substitute x = 19

21 - x + 17 + 3x = 4x

21 - 19 + 17 + 3(19) = 4(19)

2 + 17 + 57 = 76

19 + 57 = 76

76 = 76

***

Link to my CFAT Practice YouTube playlist

CFAT study guides from Amazon

***

FREE CFAT Practice Test (Canadian Forces Aptitude Test): 

https://www.army-test.com/131.html

***

CFAT Practice Test Questions with Answers in PROBLEM SOLVING - ps023

***

FREE CFAT Practice Test (Canadian Forces Aptitude Test): 

https://www.army-test.com/131.html

***

1. One half of a certain number is 5 more than 3/7 of the number. Find the number. 

a. 35

b. 70  --- answer 

c. 14

d. 5

Solution 

Let x 

= unknown number

formulate equation 

(1/2)x = 5 + (3/7)x 

(1/2)x - (3/7)x = 5 

factoring 

x (1/2 - 3/7) = 5

LCD

x ( 7 - 6 )  = 5

   ------------ 

       14

x (1/14) = 5 

x = 14 * 5

x = 70

checking 

(1/2)x = 5 + (3/7)x 

(1/2)70 =5 + (3/7)70

35 = 5 + 3(10)

35 = 5 + 30

35 = 35

2. Five loaves of bread and ten bananas have a total cost of $22.75. One loaf of bread and one banana have a total cost of $4.15. How much does a loaf of bread cost and how much does one banana cost?

a. $3.25, $0.25

b. $3.50, $0.30

c. $2.75, $0.35

d. $3.75, $0.40   --- answer 

Solution 

Let 

x = cost of one loaf of bread 

y = cost of one banana

equation1

5x + 10y = 22.75

equation2

x + y = 4.15

x = 4.15 - y

substitute the value of x in equation2 into equation1

5x + 10y = 22.75

5 (4.15 - y) + 10y = 22.75 

20.75 - 5y + 10y = 22.75

20.75 + 5y = 22.75

5y = 22.75 - 20.75

5y = 2

y = 2/5

y = $0.40 

(cost of one banana)

solve for x:

substitute the value of y into equation2

x = 4.15 - y

x = 4.15 - 0.40

x = $3.75

(cost of one loaf of bread)

***

Link to my CFAT Practice YouTube playlist

CFAT study guides from Amazon

***

FREE CFAT Practice Test (Canadian Forces Aptitude Test): 

https://www.army-test.com/131.html

***

CFAT Practice Test Questions with Answers in PROBLEM SOLVING - ps022

***

FREE CFAT Practice Test (Canadian Forces Aptitude Test): 

https://www.army-test.com/131.html

***

1. Seven years from now, Philip will be ten years younger than two times his current age. What will be his age four years from now?

a. 17

b. 34

c. 21  ---  answer 

d. 24

Solution 

step1

Solve for Philip's current age

Let: 

x 

= Philip current age

x + 7 

= Philip's age seven years from now

2x

= two times his current age

2x - 10

= ten years younger than two times his current age

Equation:

x + 7 = 2x − 10

7 + 10 = 2x - x

17 = x

x = 17

(Philip's current age)

step2

Solve for Philip's age four years from now

= 17 + 4

= 21

2. Three years ago, Jade was 14 years younger than twice her age now. How old is she seven years from now?

a. 11

b. 18  ---  answer 

c. 14

d. 22

Solution 

step1

Solve for Jade's current age 

Let: 

x 

= Jade's age now

x - 3

= Jade's age three years ago

2x

= twice her age now 

2x - 14

= 14 years younger than twice her age now

Equation:

x - 3 = 2x − 14

14 - 3 = 2x - x

11 = x

x = 11

(Jade's age now)

step2

Solve for Jade's age seven years from now

= 11 + 7

= 18 

***

Link to my CFAT Practice YouTube playlist

CFAT study guides from Amazon

***

FREE CFAT Practice Test (Canadian Forces Aptitude Test): 

https://www.army-test.com/131.html

***

CFAT Practice Test Questions with Answers in PROBLEM SOLVING - ps021

***

FREE CFAT Practice Test (Canadian Forces Aptitude Test): 

https://www.army-test.com/131.html

***

1. Determine the value of the following:

1 + 74 - 2^2 + 6 x 5

a. 385

b. 101  --- answer 

c. 25

d. 100

Solution 

using BEDMAS 

exponent

multiply 

add/subtract L-R

1 + 74 - 2^2 + 6 x 5

= 1 + 74 - 4 + 6 x 5

= 1 + 74 - 4 + 30

= 75 - 4 + 30

= 71 + 30

= 101

2. Calculate the value of:

84 ÷ (4×3) - (4+3) - 1

a.  -1   --- answer

b. 15.8

c. 16.8

d. 1

Solution 

using BEDMAS

brackets

division 

subtraction 

84 ÷ (4×3) - (4+3) - 1

= 84 ÷ 12 - 7 - 1

= 7 - 7 - 1

= 0 - 1

= -1

3. Solve the following:

62 × 6^2 - 2^3 ÷ 6^0

a. 1736

b. 2422

c. 4222

d. 2224  --- answer 

Solution 

using BEDMAS

exponents

multiply 

divide 

subtract 

62 × 6^2 - 2^3 ÷ 6^0

= 62 × 36 - 8 ÷ 1

= 2232 - 8

= 2224

***

Link to my CFAT Practice YouTube playlist

CFAT study guides from Amazon

***

FREE CFAT Practice Test (Canadian Forces Aptitude Test): 

https://www.army-test.com/131.html

***

CFAT Practice Test Questions with Answers in PROBLEM SOLVING - ps020

***

FREE CFAT Practice Test (Canadian Forces Aptitude Test): 

https://www.army-test.com/131.html

***

1. In Alberta, the average cost to paint an interior room in a house is $2.10 per square foot. A house has the following rooms for painting: 

Bedroom A: 689 sqft

Bedroom B: 746 sqft

Bedroom C: 828 sqft

Living Rm: 1727 sqft

Kitchen: 585 sqft

BathroomA: 412 sqft

BathroomB: 381 sqft

Laundry: 274 sqft

What is the total cost of painting before taxes?

a. $10,884

b. $11,488

c. $11,848  -- answer

d. $12,844

Solution 

step1 

find total sqft

=  689 + 746 + 828 +

  1727 + 585 + 412 +

   381  + 274

= 5,642 sqft

step2 

multiply total sqft by cost per sqft

Total Painting Cost

=   5,642 sqft 

   x $2.10/sqft 

= $11,848

2. The average cost to fence a yard in Canada is $55 per linear ft. If the total fencing cost of a square yard is $9,240, find the length of one side.

a. 40 ft

b. 42 ft  ---  answer 

c. 41 ft

d. 43 ft

Solution 

step1 

divide total cost by cost per linear foot

Total linear feet

= 9,240/55

= 168 ft

step2

divide total linear feet by 4 to get one side of the square yard

side of square yard

= 168/4

= 42 ft

***

Link to my CFAT Practice YouTube playlist

CFAT study guides from Amazon

***

FREE CFAT Practice Test (Canadian Forces Aptitude Test): 

https://www.army-test.com/131.html

***

CFAT Practice Test Questions with Answers in PROBLEM SOLVING - ps019

***

FREE CFAT Practice Test (Canadian Forces Aptitude Test): 

https://www.army-test.com/131.html

***

1. An investor's portfolio increased by 43.9% to $210,000. What was his initial investment?

a. $143,595

b. $145,935  --- Ans

c. $154,395

d. $149,435

Solution 

Given

43.9% increase 

$210,000 new value

let 

x = initial investment

210,000 

= x + 43.9% x

= x + 0.439x

= 1.439x

x = 210,000/1.439

x = $145,935

2. The price of gold per ounce (oz) is $1,944.10 USD. With an investment of $49,000 USD, how many ounces of gold can you purchase?

a. 23.5 oz

b. 24.2 oz

c. 22.5 oz

d. 25.2 oz  --- answer

Solution 

Divide the amount of investment by the price of gold per ounce. 

ounces (oz) of gold

= 49,000/1,944.10 

= 25.2 oz

***

Link to my CFAT Practice YouTube playlist

CFAT study guides from Amazon

***

FREE CFAT Practice Test (Canadian Forces Aptitude Test): 

https://www.army-test.com/131.html

***

CFAT Practice Test Questions with Answers in PROBLEM SOLVING - ps018

***

FREE CFAT Practice Test (Canadian Forces Aptitude Test): 

https://www.army-test.com/131.html

***

1. One week is equivalent to 604,800 seconds. If an average person sleeps 7 hours a day, what percent does an average person sleeps in a week?

a. 33%

b. 32%

c. 29%  --- answer 

d. 30%

Solution 

step1

convert 7 hours to seconds 

daily sleep sec

= 7 hr x 3600 sec/hr

= 25,200 sec/day

step2 

calculate weekly sleep in seconds 

weekly sleep sec

= 25,200 sec x 7 day

= 176,400 sec/week

step3

calculate percent sleep 

= 176,400/604,800

= 29%

2. The population of Canada on May 2023 is 39,860,000. If 23% of Canadians speak French, what number does this represent?

a. 9,178,800

b. 9,176,800

c. 9,168,800

d. 9,167,800  --- Ans

Solution 

Using long multiplication, 

= 39,860,000 x 23%

= 39,860,000 x 0.23

= 9,167,800

3. Which number is missing in the following sequence?

1/16, 1/4, 7/16, ____

a. 11/16

b. 5/8  ---- answer 

c. 3/8

d. 2/4

Solution 

The sequence is increasing by 3/16

1/16

1/16  +  3/16

= 4/16

= 1/4

4/16  +  3/16

= 7/16

7/16  +  3/16

= 10/16

= 5/8

***

Link to my CFAT Practice YouTube playlist

CFAT study guides from Amazon

***

FREE CFAT Practice Test (Canadian Forces Aptitude Test): 

https://www.army-test.com/131.html

***